Supplementary Example 2
Last updated at Aug. 24, 2021 by Teachoo
Last updated at Aug. 24, 2021 by Teachoo
Transcript
Supplementary Example 2 Find the volume of the parallelepiped whose edges are π β = 2π Μ β 3π Μ + 4π Μ, π β = π Μ + 2π Μ β π Μ and π β = 2π Μ β π Μ + 2π Μ Given, π β = 2π Μ β 3π Μ + 4π Μ , π β = π Μ + 2π Μ β π Μ , π β = 2π Μ β π Μ + 2π Μ Volume of parallelepiped = [π β" " π β" " π β ] = |β 8(2&β3&4@1&2&β1@2&β1&2)| = 2[(2Γ2)β(β1Γβ1) ] β (β3) [(1Γ2)β(2Γβ1) ] + 4[(1Γβ1)β(2Γ2)] = 2 [4β1]+3(2+2)+4[β1β4] = 2(3) + 3 (4) + 4(β5) = 6 + 12 β 20 = β2 Since volume is always positive Volume of parallelepiped = 2 cubic units
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Supplementary examples and questions from CBSE
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